Question

(A)find the torque of a force f=(i+2j-3k) about a point O.The position vector of point of application of force about O is R=(2i+3j-k)m is
(b)if the axis of rotation of the body is along the y-axis then what is the component of the torque along the axis is

Answer 1

Torque is given by cross product of r and f\[\tau =r \times f\]

Component of torque along y axis is the coefficient of j in the expression of torque.