Question

Determine the Molarity of an acid solution; if 500mL of Sulfuric acid (H2SO4)totally neutralizes 750mL of 6.412M Sodium Hydroxide (NaOH).

Answer 1

can you find the number of moles of NaOH that that was neutralized?

Answer 2

Can you walk me through it?

Answer 3

use the formula
\[\large c=\frac{ n }{ v }\]
c=concentration (measured in M)
n=amount of the substance/ no. of moles (measured in mol)
v=volume of the substance (measured in L)

Answer 4

\[\large n=cv\]
\[\large n= 6.412M~\times~750\times 10^{-3}L\]
\[\large n=??\]

Answer 5

that is finding the number of moles of NaOH..

Answer 6

what do you get for n??

Answer 7

4.809

Answer 8

sorry for not replying earlier....i had to do something for a friend...

Answer 9

you got the number of moles right....do you know about mole ratio??

Answer 10

@lovely_layne