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Determine the Molarity of an acid solution; if 500mL of Sulfuric acid (H2SO4)totally neutralizes 750mL of 6.412M Sodium Hydroxide (NaOH).
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can you find the number of moles of NaOH that that was neutralized?
Can you walk me through it?
use the formula \[\large c=\frac{ n }{ v }\] c=concentration (measured in M) n=amount of the substance/ no. of moles (measured in mol) v=volume of the substance (measured in L)
\[\large n=cv\] \[\large n= 6.412M~\times~750\times 10^{-3}L\] \[\large n=??\]
that is finding the number of moles of NaOH..
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what do you get for n??
4.809
sorry for not replying earlier....i had to do something for a friend...
you got the number of moles right....do you know about mole ratio??
@lovely_layne
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