Question

solve for the varible in this equation...
x/2-2/3=1/4

Answer 1

You would add 2/3 to both sides...to isolate where 'x' is on the left

remember you cannot add fractions without a common denominator

then divide both sides by 2

\[\frac{ x }{ 2 }-\frac{ 2 }{ 3 }=\frac{ 1 }{ 4 }\]

after adding 2/3 to both sides

\[\frac{ x }{ 2 }=\frac{ 1 }{ 4 }+\frac{ 2 }{ 3 }\]

so the least common denominator of (1/4) and (2/3) is?

Answer 2

um, 12? maybe?

Answer 3

right 12 so we can do that out now

\[\frac{ 3 }{ 12 } + \frac{ 8 }{ 12 } = \frac{ 11 }{ 12 }\]

so now we have

\[\frac{ x }{ 2 } = \frac{ 11 }{ 12 }\]

so now we multiply both fractions by 2 to completely isolate 'x'

Answer 4

okay. so how would you do that?

Answer 5

WELL IT JUST DEPENDS

Answer 6

on what?

Answer 7

\[2*\frac{ x }{ 2 } = x\]

\[2 * \frac{ 11 }{ 12 } = \frac{ 11 * 2 }{ 12 }\]

\[\frac{ 22 }{ 12 }\]

so you have

\[x = \frac{ 22 }{ 12 }\]

Answer 8

Ohhhh. So whats the answer? I et what your saying but, im very confused on how its typed out.

Answer 9

that is the answer 22/12

or if you would prefer a decimal 1.83333333333

Try and plug it into the equation for 'x'

Answer 10

It's an ugly answer I know, but sometimes that how math problems go...

Answer 11

okay, thanks.

Answer 12

no problem...I hope you understand it though?

Answer 13

once you get x/2 = 11/12....this is a proportion and you cross multiply
(12)(x) = (11)(2)
12x = 22 (now divide by 12 to get x by itself)
12x/12 = 22/12
x = 22/12 reduces to 11/6