I'm confused, can anyone explain this?

Question

anonymous · Answer

If the hypotenuse of a right triangle is 2$$\sqrt{3}$$ units long and one of the legs is $$\sqrt{3}$$ units long, then how long is the other leg?

anonymous · Answer

Your hypotenuse can be said to be "c" and the legs "a" and "b".

c^2 = a^2 + b^2

[2sqrt(3)]^2 = [sqrt(3)]^2 + b^2

b^2 = [2sqrt(3)]^2 - [sqrt(3)]^2

amistre64 · Answer

leg^2 + leg^2 = hyp^2

amistre64 · Answer

what part is the confusing part tho?

anonymous · Answer

If you can calculate:

[2sqrt(3)]^2

and 

[sqrt(3)]^2

you should have no problem.  Can you do that or do you need further help?

anonymous · Answer

Further hint:

    (m[sqrt(n)])^2   =   (m^2) ([sqrt(n)]^2)

anonymous · Answer

The classic example of this is the 30-60-90 triangle.
|dw:1370618928120:dw|

anonymous · Answer

Can you calculate:

 ([sqrt(n)]^2)    ?

In words, that means taking the square root of a number and then squaring the result.  What do you end up with?

anonymous · Answer

|dw:1370619190445:dw|