What is the perimeter of the trapezoid below?
cant see the picture, but perimeter is just adding all of the sides
do you know pythagorean theorem?
I do
so can you use that to find the missing length in your picture?
I could but what numbers would I put in? Would I put in the top and bottom numbers? Or the one on the side with either the top or bottom number?
well we know that pythagorean thm only works on right triangles, so in your figure the right triangle is |dw:1370619638197:dw|
can you solve for the missing length?
Yeah it would be \[\sqrt{136}\]
not quite, what you did was solve for the hypotenuse no one of the sides, try again
So how would I solve for one of the sides?
if the thm says \[c^2=a^2+b^2\] and c is the hypotenuse, a and b are the sides, you can solve that equation for either a or b to get you the other side
when i solve for b i get \[b=\sqrt{c^2-a^2}\]
I got 10 for B
\[b=\sqrt{100-36}=8\]
dont know how you got 10
perimeter =40
I honestly don't know how either. So would the height be 10?
you dont know how you goy 10?
Not really but I squared the square root of 136 and then subtracted 36 from 136 and then square rooted 100. If I added 10+10+14+8 it equals 42 not 40
the addition should be 10+8+8+14
that height should be 8, the equation you should solve is \[b=\sqrt{100−36}=8\]
So it would really be 40?
yep, do you see why?
I do and thanks :)
you are very welcome :)
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