Question

If 3∈A and 3B, then which of the following statements is not true?



3 is an element of B complement.
3 is an element of A∪B.
3 is an element of A∩B.

Answer 1

Your question is missing a character. Is it \(3\in A\text{ and }3\not\in B\)? or is it \(3\in A\text{ and }3\in B\)?

Answer 2

@oldrin.bataku there is a right option there, friend

Answer 3

yeah thats gibberish hah but its the e with a dash through it

Answer 4

"\(3\in A\text{ and }3B\)" makes no sense @Loser66.

Answer 5

I base on the options, there are 2 true, and 1 not true to get what the question is,

Answer 6

@miadeex that means set \(A\) contains \(3\), but set \(B\) does not.

If \(3\not\in B\) it follows that \(3\in B^c\); the complement is everything *not* in \(B\). Our first statement is true.

Since \(3\in A\) it follows that \(3\in A\cup B\), since \(A\subseteq A\cup B\) and therefore everything in \(A\) is also in \(A\cup B\). Statement 2 is also true.

Now, since \(A\) and \(B\) do not have \(3\) in common, it follows that \(3\not\in A\cap B\). Hence statement 3 is not true.