Mathematics
7 Online
OpenStudy (anonymous):
What is the cos of angle B?
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OpenStudy (anonymous):
im drawing the picture right now.
OpenStudy (anonymous):
cosine = adj/hyp
OpenStudy (anonymous):
|dw:1370652510353:dw|
OpenStudy (anonymous):
5/13
OpenStudy (anonymous):
My phone doesn't have the negative cos so i cant get the answer.
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OpenStudy (anonymous):
don't you have to do the negative cos because you are trying to find a variable?
OpenStudy (anonymous):
\[\cos = (5/13)=0.99997746\]
OpenStudy (anonymous):
did i help you?
OpenStudy (bahrom7893):
Cosine is adjacent over hypotenuse.
Cos(B) = 5/13
OpenStudy (jhannybean):
no need for law of cosines?
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OpenStudy (bahrom7893):
No.. why? You know all the sides.
OpenStudy (jhannybean):
Blah, nevermind. lol.
OpenStudy (bahrom7893):
Yea, don't overcomplicate things
OpenStudy (bahrom7893):
As per request.. solution using the law of cosines:
b^2 = a^2 + c^2 - 2a*c*Cos(B)
|dw:1370654177524:dw|
OpenStudy (jhannybean):
\[\large \cos (B) = \frac{a^2+c^2 -b^2}{2ac}\] right?
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OpenStudy (bahrom7893):
Yea
OpenStudy (bahrom7893):
12^2 = 5^2 + 13^2 - 2*5*13*Cos(B)
144=25+169-130Cos(B)
144-194 = -130Cos(B)
-50 = - 130 * Cos(B)
Cos(B) = -50/-130 = 5/13
OpenStudy (bahrom7893):
Happy?
OpenStudy (jhannybean):
\[\cos (B) = \frac{25+169-144}{2(5)(13)}\]\[\cos(B)= \frac{5}{13}\]
OpenStudy (jhannybean):
:D yes.