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Mathematics 7 Online
OpenStudy (anonymous):

What is the cos of angle B?

OpenStudy (anonymous):

im drawing the picture right now.

OpenStudy (anonymous):

cosine = adj/hyp

OpenStudy (anonymous):

|dw:1370652510353:dw|

OpenStudy (anonymous):

5/13

OpenStudy (anonymous):

My phone doesn't have the negative cos so i cant get the answer.

OpenStudy (anonymous):

don't you have to do the negative cos because you are trying to find a variable?

OpenStudy (anonymous):

\[\cos = (5/13)=0.99997746\]

OpenStudy (anonymous):

did i help you?

OpenStudy (bahrom7893):

Cosine is adjacent over hypotenuse. Cos(B) = 5/13

OpenStudy (jhannybean):

no need for law of cosines?

OpenStudy (bahrom7893):

No.. why? You know all the sides.

OpenStudy (jhannybean):

Blah, nevermind. lol.

OpenStudy (bahrom7893):

Yea, don't overcomplicate things

OpenStudy (bahrom7893):

As per request.. solution using the law of cosines: b^2 = a^2 + c^2 - 2a*c*Cos(B) |dw:1370654177524:dw|

OpenStudy (jhannybean):

\[\large \cos (B) = \frac{a^2+c^2 -b^2}{2ac}\] right?

OpenStudy (bahrom7893):

Yea

OpenStudy (bahrom7893):

12^2 = 5^2 + 13^2 - 2*5*13*Cos(B) 144=25+169-130Cos(B) 144-194 = -130Cos(B) -50 = - 130 * Cos(B) Cos(B) = -50/-130 = 5/13

OpenStudy (bahrom7893):

Happy?

OpenStudy (jhannybean):

\[\cos (B) = \frac{25+169-144}{2(5)(13)}\]\[\cos(B)= \frac{5}{13}\]

OpenStudy (jhannybean):

:D yes.

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