Question

For this right triangle, what is the cosine of angle C?

Answer 1

adjacent over hypotenuse

Answer 2

SOH CAH TOA.

Sine, Opposite over Hypotenuse
Cosine, Adjacent over Hypotenuse
Tangent, Opposite over Adjacent

Answer 3

but you don't know the adjacent side yet, you need to find it
pythagoras tells you that
\[5^2+b^2=13^2\]
\[25+b^2=169\]
\[b^2=144\]
\[b=12\]

Answer 4

or you can just memorize the \(5-12-13\) right triangle, it is a favourite of math teachers

Answer 5

A: 12/13
B: 13/12
C: 5/12
D: 5/13

Answer 6

b^2 = 13^2 - 5^2

b = sqrt( 169-25) = 12

cos(c) = b/13

Answer 7

only one most of them know besides \(3-4-5\)
in any case it is
\[\cos(C)=\frac{opp}{hyp}=\frac{12}{13}\]

Answer 8

Wow; that helped a ton. Thank you bunchessss!

Answer 9

I'm horrible in mathh.