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Mathematics 6 Online
OpenStudy (anonymous):

Which of the following is the solution of a - 4 > 1 and a + 2 < 1? Answer All Real Numbers No Solution what does is mean real number or no solution?

jimthompson5910 (jim_thompson5910):

let's solve each inequality one at a time

jimthompson5910 (jim_thompson5910):

what do you get when you solve a - 4 > 1 for 'a'

OpenStudy (anonymous):

5

jimthompson5910 (jim_thompson5910):

what about 5

OpenStudy (anonymous):

a>5

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

how about a + 2 < 1 what do you get when you isolate 'a'

OpenStudy (anonymous):

a<-3

jimthompson5910 (jim_thompson5910):

close

jimthompson5910 (jim_thompson5910):

1 - 2 isn't 3 though

OpenStudy (anonymous):

a<-2

jimthompson5910 (jim_thompson5910):

1 - 2 is like saying "I have 1 dollar and I'm going to spend $2, so I'll be 2-1 = 1 dollar in debt...ie have a balance of -1 dollars"

jimthompson5910 (jim_thompson5910):

so 1 - 2 = -1

jimthompson5910 (jim_thompson5910):

which means a + 2 < 1 turns into a < -1

OpenStudy (anonymous):

ok i did 1-3 oops!

jimthompson5910 (jim_thompson5910):

that's ok

OpenStudy (anonymous):

so then it is real numbers

jimthompson5910 (jim_thompson5910):

hold on

jimthompson5910 (jim_thompson5910):

This means a - 4 > 1 and a + 2 < 1 turns into a > 5 and a < -1

jimthompson5910 (jim_thompson5910):

so is there such a number that is a) greater than 5 AND b) less than -1 at the same time?

OpenStudy (anonymous):

No solution

jimthompson5910 (jim_thompson5910):

correct, there are no real numbers that satisfy all the conditions at once

OpenStudy (anonymous):

That makes sense thanks

jimthompson5910 (jim_thompson5910):

yw

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