Question

How to prove whether the sequence is AP (arithmetic) or GP (geometric)?

Answer 1

For an AP.. the common difference of the terms should be constant..
suppose the first term is a.. the second term would be of the form a+d, third term a+2d, fourth term a+3d.. and so on.. where d could be positive or negative..

Answer 2

i know that bt..

Answer 3

but?

Answer 4

Tn= (Tn-1)^2, T1= 7

Answer 5

how can i prove it....with the working out for both AP and GP

Answer 6

i am sorry, but i dont really get your question. what do you have to prove?

Answer 7

whether this sequence is AP or GP?

Answer 8

i think its none bt not sure

Answer 9

Umm no.. wait i'll write it again. i messed it up.

Answer 10

Tn= (Tn-1)^2
Just solve this.. you would finally get a constant Tn.. So the progression is like Tn, Tn, Tn, Tn.... So its an AP with common difference 0.. and a GP with common ration 1..
T1=7.. i dont really know why its given..

Answer 11

so... i cant use half of the q' to solve it

Answer 12

well, thats what i make of the question. wait for someone else to help you with it.

Answer 13

ok thanks anyways

Answer 14

isn't it,
\(\huge (T_{n-1})^2\)
or
\(\huge (T_n-1)^2\)
?

Answer 15

the ist one

Answer 16

Eh, i misread the statement. :/

Answer 17

so, T1 =7, T2 = 7*7 =7^2, T3 = 7*7*7*7=7^4 ...
7^1,7^2,7^4,7^8 ....and so on,
do you find a common difference or common ratio ???

Answer 18

none

Answer 19

thats correct, that sequence is neither AP, nor GP

Answer 20

yeah thats wht i thought 2 bt wasnt sure

Answer 21

thanks

Answer 22

welcome ^_^