Question

light of wavelength 1288 A is emitted when the hydrogen atoms drop from 5th to 3rd orbit.find the wavelength of ohoton emitted when electrons falls from 3rd to 2nd orbit????? plzz tell me

Answer 1

do you know what formula to use?

Answer 2

\[E=h \nu = h \left[ R \left( \frac{ 1 }{ n _{low}^{2} }-\frac{ 1 }{ n _{high}^{2} } \right) \right]\]
h = planck's constant = \[h = 6.626 \times 10^{-34}\]

Answer 3

yess i know formulaa tell me wht is the nxt step after thisss

Answer 4

yess i know formulaa tell me wht is the nxt step after thisss

Answer 5

obtain the frequency
\[\nu\]

Answer 6

\[R = 3.29 \times 10^{15}\]

Answer 7

\[\nu = R(\frac{ 1 }{ n _{low}^{2} }-\frac{ 1 }{ n _{high}^{2} })\]
\[=3.29 \times 10^{15} \left( \frac{ 1 }{ 2^2 } - \frac{ 1 }{ 3^2 } \right)\]

Answer 8

it is necessary to obtain the frequency first since we need it to obtain the wavelength
recall the formula
\[\lambda \nu = c\]
where:
ƛ wavelength
ν frequency (sometimes f is used)
c speed of light 2.9979 x 10^8 m/s

the speed of light is constant so we don't need to calculate that, thus leaving us only the frequency to solve in order the obtain the wavelength