Question

Solve this quadratic equation.

x^2 + 2x - 22 = 0

Answer 1

What we have to do in this? :/

Answer 2

I mean solve it by quadratic formula?

Answer 3

I believe so?

Answer 4

The answer is x= -1 plus/minus sqrt(23)

Answer 5

I just need to know how to get there.

Answer 6

LOL @Euler271 explained you na try to do it yourself :P

Answer 7

\[x_{1,2} = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\]

for the equation in the form ax^2 + bx + c

Answer 8

in the form ax^2 + bx + c = 0 **

Answer 9

let me know if you want the next step

Answer 10

LOL let him do it xD

Answer 11

46 is what I get.

Answer 12

@tcarroll010 that is confusing :o :/

Answer 13

a = 1; b = 2; c = -22

\[x_{1,2} = \frac{ -2 \pm \sqrt{2^2 - 4(1)(-22)} }{ 2(1) } = \frac{ -2 \pm \sqrt{92} }{ 2 }\]

Answer 14

mmhmm

Answer 15

\[= \frac{ -2 \pm \sqrt{4}\sqrt{23} }{ 2 } = -1 \pm \sqrt{23}\]

Answer 16

@emcrazy14 Where did the sqrt(4) and 23 come from?

Answer 17

@who? lol
\[\sqrt{a} \times \sqrt{b} = \sqrt{ab}\]

Answer 18

lol meant @Euler271 anyway, i thought a was 1 and b was 2??

Answer 19

this is in a general case. for any two numbers a and b

Answer 20

ah,

Answer 21

\[\sqrt{92} = \sqrt{4 \times 23} = \sqrt{4} \times \sqrt{23}\]

Answer 22

Ah. Makes sense. Thanks!!!!!!