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Mathematics 8 Online
OpenStudy (zzelinski):

question coming

OpenStudy (zzelinski):

Find the domain of \[ \frac{ 3x-5 }{ 5x-35 }\]

OpenStudy (tkhunny):

Factor what can be factored and you should see it.

OpenStudy (zzelinski):

I forgot how to factor?

OpenStudy (zzelinski):

I got \[\frac{ 3x }{ 5x+7 }\] but I'm not sure its right....

OpenStudy (tkhunny):

Seriously? No, you didn't. I am certain you can change \(5x-35\) into \(5(x-7)\).

OpenStudy (tkhunny):

Factors and terms are not the same thing. All there is to do with this expression it to factor the denominator.

OpenStudy (tkhunny):

\(\dfrac{3x-5}{5x-35} = \dfrac{3x-5}{5(x-7)}\) That's it. Now, what happens when you try x = 7 in that last expression?

OpenStudy (zzelinski):

I got 16

OpenStudy (tkhunny):

Try again. If x = 7, what is x-7?

OpenStudy (zzelinski):

I got 16 again....I see what you're saying, that like \[x\neq 7\] I'm sorry, my brain just isn't working right today x(

OpenStudy (tkhunny):

You cannot get 16. The denominator is zero (0)! You seem to be ignoring that important fact.

OpenStudy (zzelinski):

Oh...its undefined...? I have a feeling this is wrong, as well. Thanks for your help, I'm going to try this problem again later.

OpenStudy (tkhunny):

That's the spirit. Now, please work on your factoring. You WILL need to know the difference between a TERM and a FACTOR. Good luck.

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