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Partial derivatives of e^(x/y)
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$$\frac\partial{\partial x}e^{\frac{x}y}=\frac1ye^{\frac{x}y}$$Can you do \(\dfrac\partial{\partial y}\)?
xe^(x/y)?
@oldrin.bataku
Pretend \(x\) is a constant \(k\) and try determining$$\frac{d}{dy}e^{\frac{k}y}$$Note you'll need to use the chain rule... can you figure out the derivative of \(\dfrac{k}y\)?
Isn't the derivative of k/y: -k/(y^2)
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Right! So instead of \(k\) we have \(x\) and it's a *partial* derivative:$$\frac\partial{\partial y}\frac{x}y=-\frac{x}{y^2}$$Can you try completing \(\dfrac\partial{\partial y}e^{\frac{x}y}\)?
\[-\frac{ x }{ y ^{2} }*e ^{\frac{ x }{ y }}\]
@oldrin.bataku
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