A ball is thrown straight down from the top of a 449-foot building with an initial velocity of -30 feet per second. Use the position function below for free-falling objects.

s(t) = -16t^2 + v sub0 t + s sub0

What is its velocity after falling 376 feet?

Question

A ball is thrown straight down from the top of a 449-foot building with an initial velocity of -30 feet per second. Use the position function below for free-falling objects.

s(t) = -16t^2 + v sub0 t + s sub0

What is its velocity after falling 376 feet?

anonymous · Answer

position equation 
 s(t) = -16t^2 + vo t + so

vo = -30
so= 449

first determine the position after it has fallen 376 ft
which would be 449- 376

then determine the time at the at that position

once you've determined the time

use the velocity equation or find the derivative of the position equation and substitute the time determined to find the velocity after it has fallen 376 ft

anonymous · Answer

thanks! thats what I was thinking but i am having trouble finding the time help please :)