Question

Guys, please help. I suck at these problems, on my finals' review, question is in the comments.

Answer 1

ok I will help but you must help me

Answer 2

My question:
\[\text {One number is 3 more than another. Twice the smaller is equal to 5 times the larger}\] \[\text {decreased by 3. Find the numbers.}\]

Answer 3

ok i am on it

Answer 4

Part 4: Translate and solve: 25. 6 less than twice a number is ten Answer : 2n - 6 = 10 (answer: n = 8) 26. The quotient of a number and 4 plus 3 is 8 Answer: n/4 + 3 = 8 (answer: n = 29) 27. 4 less than three times a number is -28 Answer: 3n - 4 = -28 (answer: n = -8) 28. ...

Answer 5

???
First thing to do is represent, it's always the first thing to do in word problems ^.^

Answer 6

@JordanFeinstein Please don't jsut copy/paste the answers, as it's concidered cheating according to the CoC, which can be found at: http://www.openstudy.com/code-of-conduct

@PeterPan That's the problem, I suck at setting these problems up.

Answer 7

okay, what's your favourite letter?

LOL
I'm just kidding, I don't care what your favourite letter is, I'll use x anyway :P

Anyway seriously... take things one at a time...
-One number...-
(let's call this x)

-...is three more than than another number-

everything ok (so far) ?
^.^

Answer 8

So then it would be: \[x + (3 \times x)\] then what would be next?

Answer 9

"three MORE THAN" should be a cue for addition and not multiplication ;)

Answer 10

question: are we supposed to be working with two variables here or just one?

Answer 11

Just one variable.

Answer 12

okay :)
So you have two missing numbers, one of them is x, the other one,
x is bigger than that other one, by 3, aye? :D

Answer 13

its asking for 2 numbers, a smaller and a larger
2 variables :)

Answer 14

this is the problem: One number is 3 more than another. Twice the smaller is equal to 5 times the larger decreased by 3. Find the numbers. right now, we have \[x + (3+x)\] right?

Answer 15

Okay, you know what, let's let x be the smaller number instead...

Answer 16

So if x is the smaller number, and the bigger number is bigger than the smaller number BY THREE, then the bigger number should be x + 3, right? :)

Answer 17

Aye, but its the same thing just put a different way.

Answer 18

Yup :)
So let's get back to it...
-twice the smaller number-
How do you represent that? Remember, x is the smaller number... ^.^

Answer 19

I have no clue. >.<

Answer 20

Twice is multiplying by 2 :)
Twice the smaller number --> 2x
okay? ^.^

Answer 21

Aye, so then you would have: \[2x+(3+x)\] Is that right?

Answer 22

Not quite :)
Let's not get ahead of ourselves yet :D

Answer 23

-twice the smaller number-
(that's 2x)
-is equal to-
(2x = ...)


-five times the larger number-

Okay, so how to represent 5 times the larger number? (remember, the larger number is x+3)

Answer 24

erm. Is it: \[2x=5\times (x+3)\] by any chance?

Answer 25

yes, but ... at the end, we're not yet finished...

-twice the smaller number is equal to five times the larger number DECREASED BY THREE-

So it should be
\[2x = 5\times (x+3) \color{red}{-3}\]

Because of the decreased by three bit at the end...

Answer 26

And here, you're ready to solve for x ^.^

Answer 27

Because we have successfully represented the entire problem--

Answer 28

everything all right? ^.^

Answer 29

Where'd the little -3 come from? Sorry, didn't go during the lag.

Answer 30

the little -3 comes from the bit at the end that says DECREASED BY THREE
^.^

Answer 31

Decreased means subtract ^.^

Answer 32

*grumbles to him self lowly thinking of how mad he is because he didn't see that* Well then. Lets get to it, shall we?

Answer 33

Lead the way :D

Answer 34

Why don't you start with distributing this part
\[2x = \color{blue}{5\times(x+3)}-3\]

Answer 35

Err. I don't know what i'm doing. And I have to get to my ASL class. dang it, TTYL talk to you tomorrow.

Answer 36

aww, and we were just getting to the fun part... oh well :)

Answer 37

Tell me about it. >.<

Answer 38

Have fun ^.^