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Chemistry 12 Online
OpenStudy (anonymous):

Which of the following has a standard enthalpy of formation value of zero at 25 degree C? a. O2 (s) b. O (g) c. O2 (g) d. O3 (g) e. O2 (l) I know it is O2 (l) but really don't understand why, please explain from the simplest concepts! So confused. Thanks!

OpenStudy (chmvijay):

All elements in their standard states (oxygen gas, solid carbon in the form of graphite, etc.) have a standard enthalpy of formation of zero, as there is no change involved in their formation. ther for the answer would be O (g)

OpenStudy (chmvijay):

enthalpy of an element in its standard state is zero.

OpenStudy (anonymous):

Hmm, okay, but how do I know what their standard state is? Why is O2 in gas form its standard state? I can't seem to figure that out anywhere.

OpenStudy (chmvijay):

noo all elements will be in their standard form :) that you should know by basic knowledge in periodic table they mention all the elements standard state :) O2 is molecule hence its not an element it cant be zero:)

OpenStudy (anonymous):

Hmm, I guess I'm still kind of confused. I guess I don't get why O2 (g) is correct when O2 (l) isn't, or even why all of these wouldn't be correct since they are all elements & not compounds? Haha sorry, I'm just not getting this concept!

OpenStudy (chmvijay):

O(g) is correct and not O2(L) or O2 (g) O is element and O2 is molecule like a compound

OpenStudy (anonymous):

Hmm, my instructor marked that O2 (g) is the correct answer, but your explanation makes more sense. \: Maybe he made a mistake. So if there were another question like this, it would be the pure element then?

OpenStudy (chmvijay):

yaaa :)

OpenStudy (anonymous):

Alright, thank you very much! (: Makes sense.

OpenStudy (chmvijay):

you are welcome :)

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