Question

factor (p+3q)-r(3q+p)

Answer 1

A little (just a little) tricky, but you only need to remember two things:
FIRST
a + b = b + a

And SECOND
ac + bc = c(a + b)

Answer 2

So, the r(3q+p) may be written instead as
r(p+3q)

Turning this expression into
(p+3q) - r(p+3q)

Answer 3

so now i have (p+3q)-rp-3qr ?

Answer 4

No. While that is technically correct, you're being asked to factor, not distribute.

Distributing is in fact a step backwards when it comes to factoring...

Just remember

ac + bc ----> c(a + b)

Answer 5

so what do i do ?

Answer 6

Do you not see anything that looks like this?
ac + bc ?

Maybbe
ac - bc ?

It works on the same principle

ac - bc = c(a - b)

Answer 7

And you can be quite flexible when it comes to your choice of "c"

Answer 8

can you tell me the setup ? then ill solve it

Answer 9

Okay, why don't we let
c = (p + 3q)

So now, we have
c - rc

Does that look more agreeable to you? :)

Answer 10

do you know what the answer is ?

Answer 11

No ;)

Answer 12

can you just set up the problem for me ?

Answer 13

I am...
We let c = (p + 3q)
So that the expression becomes
c - rc

so use that second concept I told you, the one involving distribution...