Question

Evaluate log9 27?

Answer 1

27=3^3
9=3^2

so it's 3/2

Answer 2

\(9^x=27\) is a start

Answer 3

then since \(9=3^2\) and \(27=3^3\) you get \[3^{2x}=3^3\iff 2x=3\]

Answer 4

key step is to know that
\[\log_b(y)=x\iff b^x=y\]