The vertices of a quadrilateral ABCD are A(1, -3), B(4, -3), C(4, -5), and D(-1, -5). The vertices of another quadrilateral EFCD are E(1, -7), F(4, -7), C(4, -5), and D(-1, -5). Which conclusion is true about the quadrilaterals? The shape of the quadrilaterals is same but their areas are different. The ratio of their corresponding sides is not equal. The measures of the corresponding angles are different. The angles and sides overlap when one quadrilateral is placed on the other.
meegan can u help me again??
so, have you tried drawing them on the cartesian plane?
so, they each look like above what do you think?
i tried on geogebra
so, which of those statements is true then? :)
idk the last one
is it okay
?????
well, only 2 angles and 1 side overlap there, so, if by "the angles" means all angles, then that's false then again, the shape is the same, and they're both the same area, because they're equal so is not the 1st one the ratio of the corresponding sides ARE equal :/, so is not that the measures of the corresponding angles ARE the same, so is not that either
so, all of the above, to me seems to be false :/
so which one??
ööö
the one that I säid
??
ahhemm, which one? none as far as I can tell, but I'm thinking the last one, yes, I gather they mean, "if we turn EFCD on its head and place corresponding sides on top of each other", they yes, if that's done, yeah, their sides and angles will overlap
ok thanks+
yw
hey can u still help me
jdoe0001
sure, but is easier and better if you post in the channel, so we all can see it and help and revise each other :)
okay I will post a new one
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