Question

Help Please! (:

Solve each equation by completing the square:

Answer 1

\[k^2-8k-48=0\]

Answer 2

Why not use the quadratic formula?

Or - you can factor the equation. Can you do that for me?

Answer 3

oh come on, completing the square is so much fun though :)

Answer 4

Haha! @dumbcow :P

Answer 5

wut. No, it's a trinomial. You can factor it into two binomials.

Answer 6

Factor. Have you taken 8th grade math, hun? Do you know how to factor a trinomial?

Answer 7

if her directions say to complete the square, that is the way she should do it...

Answer 8

\[k^{2} -8k = 48\]
\[k^{2} - 8k+(\frac{8}{2})^{2} = 48 + (\frac{8}{2})^{2}\]
\[k^{2} -8k +16 = 64\]
\[(k-4)^{2} = 64\]
\[k-4 = \pm 8\]
\[k = -4 , 12\]

Answer 9

@dumbcow Thanks so much! Much appreciated!! GBU!! (:

Answer 10

hopefully you understand the steps and @Compassionate has a point , at this stage of math you should be able to easily factor this quadratic as well

Answer 11

Exactly. Like Dumbcow said. I was surprised that you're working on Quadratics and don't even know how to factor a trinomial.

Answer 12

\[k^{2} -8k -48 \]
2 num that multiply to -48 but add to -8
-12*4 = -48
-12 +4 = -8
\[\rightarrow (k-12)(k+4)\]