find the exact value of the expression. 1. cos^-1 (-√ 3/2) 2. tan^-1 (-1) 3. sin(tan^-1 2) 4. cos (sin ^-1 3/5)
well, get your Unit Circle :), and that'd show you who is who
1st is usually a given in most unit circles the 2nd one, tan = y/x, so where "y" and "x" have the same value, they'd give 1, and when either is negative, they'd give -1
the 3rd one you'd firstl need to find the angle WHOSE tangent is 2, or WHOSE y/x is 2, is a positive 2, so,"y" and "x" are either both positive or both negative
the 3rd one and 4th one, don't seem to be any of the "regular usual" angles in most unit circles, so, seem you may end up using your calculator for those
so what does the inverse have to do with this?
is not an inverse, is a misnomer, or miswriting per se (cos/sin/tan)\(\large ^{-1}\) simply means what is the angle WHOSE cos/sin/tan is THIS NUMBER?
so an easy one, number 2) \(tan^{-1}(1)\) what is the angle WHOSE tangent is 1? well, taking a peek at my unit circle, \(45^o\) has a sine and cosine which are exact, value and sign so, 2nd quadrant they differ in sign so 3rd quadrant, they're the same in sign, I check the "reference angle" for 45, that is 180+45, low and behold, they're both the same value, so \(\cfrac{same}{same}\) = 1 so, those are the angles WHOSE tangent is 1
the questions actually says tan^-1 (-1) but does that change anything?
well \(\cfrac{same}{-same}\ \ or \ \ \cfrac{-same}{same} \implies -1\)
so then it would be either 7pi/4 or 3pi/4 correct?
yes, it'd be both
ok so my problem is, the answer to this one problem is supposed to be -pi/4...
well, no
the negative exponential in trig identities, doesn't stand for any reciprocal :/, unfortunately, is a misnomer, it really just mean what is the angle whose function gives this value? say cos(x) = 1234567 so, if I were to ask, what is the value whose cosine is "1234567"? or \(\color{red}{cos^{-1}(1234567)}?\) well, since the cos(x) = 1234567, so the angle would be "x"
Join our real-time social learning platform and learn together with your friends!