Question

Thank you

Answer 1

Okay, you've got 3 entrees, A, B, and C. You've got 3 vegetables, X, Y, and Z

For entree A, you can have any of X, Y, Z, so AX, AY, AZ are the possible combinations.
For entree B, you can have any of X, Y, Z, so BX, BY, BZ are the possible combinations.
For entree C, you can have any of X, Y, Z, so CX, CY, CZ are the possible combinations.
Altogether, the different meals that could be ordered are
AX, AY, AZ, BX, BY, BZ, CX, CY, CZ

9 in total. 3 choices for the first, 3 independent choices for the second, so 3*3 = 9.

Answer 2

WOW thank you. Ok going to read it just sec.

Answer 3

ok so you took A,B and C then for each x, y and z then added it all up. then I see 3 choices for each I mean 3 + 3 +3 = 9 or 3 x 3 = 9. Ok thank you @whpalmer4

Answer 4

It might be instructive to think of this as a tree diagram.

Answer 5

yes : )

Answer 6

I'm writing your notes down. GOt a large math note book full of my notes.

Answer 7

thank you going to try and print it @whpalmer4

Answer 8

How did you do that diagram?? @whpalmer4

Answer 9

I drew your diagram for my note book. Thanks @whpalmer4

Answer 10

Here's an example of where the tree is perhaps more useful. We flip a coin twice in succession, and want to figure out the probability of having two heads results in a row.

Answer 11

After the first flip, half of the remaining possibilities are ruled out, though we still have to enumerate them to get the total count of possible outcomes. After the second coin flip, 3/4 of the possibilities have been ruled out, leaving just 1 green node and 3 red nodes as "leaves" in the tree.

Answer 12

I used a Mac (or iPad) app called OmniGraffle to do the diagrams. No particular endorsement implied, it's just what I happen to have handy.