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A railroad tunnel is shaped like a semi ellipse as shown below. The height of the tunnel at the center is 27 ft and the vertical clearance must be 9 ft at a point 24 ft from the center. Find an equation for the ellipse.
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|dw:1370902910739:dw|
the equation of the ellipse is y^2/a^2 + x^2/b^2 = 1 We also know that the maximum y value is 27, so y^2 / 729+ x^2/b^2 = 1 Now it's just a matter of finding b. In order to do so, just plug in the x and y values you're given
9^2/729 + 24^2/b^2 = 1 ? - ?/729 = 24^2/b^2 solve b and the ?-? from here and you have your ellipse. hope this helps
I got 81/729+576/b^2=1
@jslp3z
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So 81/729=576/b^2?
i believe that is correct !
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