Okay, so I have to see if I did this correctly(: Use the given equations to find the missing domain and range elements: y=-3x+5 Domain Range x y --------------- -3 0 7 1 4 So I got: -3 10 0 -5.5 ? 7 1 4 4 2.5
if x = 1, y = -3 + 5 = 2. The line 1 4 should be 1 2
Oh my gosh! I put the wrong equation up! SORRY! Its \[x^2-2y=11\]
if x = 4, y = -3*4 + 5 = -12 + 5 = -7 line 4 2.5 should be 4 -7 Try to find the value of x that gives y = 7 :]
wow, it changes everything...
x = -3, you will have: (-3)² - 2y = 11 9 - 2y = 11 9 - 11 = 2y y = -1
x = 0 it's correct. for x = 1 1² - 2y = 11 1 - 2y = 11 1 - 11 = 2y -10 = 2y y = - 5 x = 4 its correct.
With y = 7, x² - 14 = 11 x² = 25 x = 5
So: -3 -1 0 -5.5 5 7 1 -5 4 2.5
Yea!
Thanx so much!!! Much Apreciated!! GBU!! :)
Oh, a problem!! In the line 5 7 it's +- 5.
x² = 25 gives the solution x = 5 and x = -5
haha(: thanx!
so instead of 4 and 2.5 its 5 and -5
no no
In the row: 5 7 (x = 5, y = 7) Its correct, however, -5 7 is correct too.
Because you have to find the value of x that gives you y = 7, and x = 5 and x=-5 gives this. Just try: x² - 2y = 11 (5)² - 2y = 11 25 - 2y = 11 14 = 2y y= 7 (-5)² - 2y = 11 25 - 2y = 11 14 = 2y y = 7
Haha, thank!
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