What are the steps to solve the following Differential Equation?

y' = cos(2y-2x)

Thank you in advance

Question

What are the steps to solve the following Differential Equation?

y' = cos(2y-2x)

Thank you in advance

anonymous · Answer

Any initial conditions?

anonymous · Answer

Nope

anonymous · Answer

Change it to$$\frac{ dy }{ dt }=\cos(2y)\cos(2x)-\sin(2y)\sin(2x)$$

anonymous · Answer

BTW, is this FOR differential equations class?

anonymous · Answer

I am studying for an exam and have come to this subject.Thank you for your response

anonymous · Answer

Is this for differential equations class though or for some different class?

anonymous · Answer

It's for a class in Applied Mathematics

anonymous · Answer

After DiffEQ, or before it?

anonymous · Answer

We are doing Differential Equations and Functions with Many Variables amongst other things in this class for the first time

anonymous · Answer

You're an undergrad stud right?

anonymous · Answer

Yeah

anonymous · Answer

What I would do is just use the equation above and then use two separate integrals and then since you're trying to undifferentiate X, just pull out the y terms and then integrate the X terms then you'll have your answer

anonymous · Answer

OK! Thank you very much!