Question

(4x3 + 7x2 – 13x – 3) ÷ (x + 3)
use synthetic division to solve this problem

Answer 1

i got this so far
3) 4 7 -13 -3
12 -15 6
4 -5 2 -3

Answer 2

Okk. but can you help me with this question.

Answer 3

LOL YEA FAN ME

Answer 4

i am afraid, my dear, you made the same mistake as last time

Answer 5

remember when you divided by \(x-7\) and you had to make sure to put a \(7\) on the side, rather than \(-7\) ?

Answer 6

in this case you have \(x+3\) so guess what you have to put on the side?

Answer 7

-3?

Answer 8

yes

Answer 9

Okk thank you. One sec im going to try again.

Answer 10

that is why you get to add instead of subtract when you do these
that is the reason you want to put \(-3\) on the side, so you don't have to worry about subtracting like you do with long division

Answer 11

Please see the attached file.

Answer 12

-3) 4 7 -13 -3
-12 -15 -6
4 -5 -2 -3

Answer 13

oohh thank you @adinarayan and @satellite73 . i see what ii did wrong . (: You guyrs were alot of help.

Answer 14

yw

Answer 15

No problem. Thanks for the compliment. :)

Answer 16

Wait , sorry. so is this the answer ?
x^3+4x^2-5x+2 R-9

Answer 17

no i think there was a mistake in the answer given above

Answer 18

:( . What was it ?

Answer 19

lets re do it as you were doing it

Answer 20

-3) 4 7 -13 -3
-12 -15 -6
4 -5 -2 -3

Answer 21

4 7 -13 -3
-3 -12 15 -6
4 -5 2 -9

Answer 22

your \(-15\) should be \(15\) and \(-13+15=2\)

Answer 23

are you happy with my last line at the bottom?

Answer 24

My gosh, I'm sorry. Did I give an incorrect answer? I honestly apologize, it won't happen again... :(

Answer 25

if so, now that we have the last line as
4 -5 2 -9 we have to know how to read off the answer

Answer 26

you have a polynomial of degree 3, divided by a polynomial of degree 1 leaving a polynomial of degree 2
the coefficients are there, so your answer is
\[4x^2-5x+2\] with a remainder of \(-9\)

Answer 27

okkk yes. i had got that @satellite73 but im not sure how to write it after i get that. and @adinarayan nooo its okk. i just was wondering how would i write the answer you agve me. x^3+4x^2-5x+2 R-9?

Answer 28

you could write
\[4x^2-5x+2-\frac{9}{x+3}\]

Answer 29

@adinarayan i make mistakes all day, you will make more, i am sure of it

Answer 30

i like to think of them as "typos"

Answer 31

thank you. do you guys mind helping in another question?

Answer 32

(3x3 – 4x – 1)÷ (x + 1)

Answer 33

-1) 3 -4 -1
-3 1
3 -1 0
(3x^2-1)

Answer 34

is it right?

Answer 35

No.\[3 x^3-4 x-1=(x+1) \left(3 x^2-3 x-1\right) \]

Answer 36

another very very common mistake
in this one you forgot to hole the place of the missing term

Answer 37

sorry im confused.

Answer 38

\[3x^3 – 4x – 1\] you need to put a \(0\) in the \(x^2\) place, as that term is missing

Answer 39

when you list the coefficients, you have to keep the place of any missing power
you are writing in descending order of the powers
since there is no \(x^2\) term you have to hold the \(x^2\) place with a \(0\). more simply put, the coefficients are
\[3, 0, -4, -1\]

Answer 40

set up should look like
3 0 -4 -1
-1)

Answer 41

it is a very common mistake, make sure to look out for it

Answer 42

oooohhh. okkk .
sooo
-1) 3 0 -4 -1
-3 3 1
3 -3 -1 0

Answer 43

got it !

Answer 44

that is why the answer is what @robtobey wrote
\[3x^2-3x-1\] and no remainder

Answer 45

thankk youu . (:: . i just have three more queestions i need help on.

Answer 46

post em

Answer 47

make a new thread