Question

( x4 – 8x3 + 16x2 – 19 )÷ (x -5)
use synthetic division to solve this problem

Answer 1

@satellite73

Answer 2

5) 1 -8 16 -19
5 -15 5
1 -3 1 -14

Answer 3

DON'T FORGET TO HOLD THE PLACE!!!

Answer 4

what term is missing?

Answer 5

@satellite73 How does someone get an SS of 100? lol sorry I just wanna know

Answer 6

start at the dawn of time, then spend all waking hours here

Answer 7

Maybe I will be there sometime! I'd be closer if I didn't keep procrastinating on my own studies! :D

Answer 8

i bet you can solve it now right?

Answer 9

5) 1 -8 16 0 -19
5 -15 5 1 5
1 -3 1 5 -4

Answer 10

looks much much better!

Answer 11

Okk Thankyou (: . Now how do i write it though ?

Answer 12

you have a polynomial of degree 4 divided by a polynomial of degree 1
what is the degree of your answer?

Answer 13

3?

Answer 14

yes

Answer 15

and you have the coefficients

Answer 16

-3x^3+x^2-5x -4
-----
x – 5

Answer 17

no you forgot the first 1

Answer 18

bottom row is
1 -3 1 5 -4

Answer 19

x^4 -3x^3+x^2-5x -4
-----
x – 5

Answer 20

im getting confused :(

Answer 21

polynomial should be degree 3, not 4

Answer 22

i see the confusion
you have a constant, and also a remainder
the constant is the second to last number
the remainder is the last number

Answer 23

the last row is
1 -3 1 5 -4
try again, but this time start with \(x^3\)

Answer 24

5 is the constant, no \(x\) there

Answer 25

x^3 -3x^2+x-5 -4
-----
x – 5

Answer 26

tada!

Answer 27

Omgg . YOu Great ! Thankyou !

Answer 28

except...

Answer 29

1 -3 1 5 -4
\[x^3-3x^2+x+5-\frac{4}{x-5}\]

Answer 30

you had \(-5\) as the constant, but the bottom row had \(5\) not \(-5\)
maybe it was a typo

Answer 31

ohh yea sorry. your right. okk i have two more and then im done . im going to open them in a new thread. (;

Answer 32

k