Question

Which of the following is(are) equivalent to 3333 base seven + 3333 base seven?

(i) 6666 base seven

(ii) 1480 base twelve

(iii) 10000 base seven

A) (i) only
B) (iii) only
C) (i) and (ii) only
D) (ii) and (iii) only

Answer 1

these problems are all over the map
what kind of class is this?

Answer 2

Well we know (i) and (iii) are not equivalent and in fact are off by 1. We also know (i) is equivalent to our asked expression, allowing us to eliminate options (B) and (D).

Answer 3

why isn't (i) right?

Answer 4

It is a prereq class. I have to take 2 of these before I can start any college level math courses.

Answer 5

jesus they must hate you

Answer 6

oh i see @oldrin.bataku you did not say it was not right, sorry

Answer 7

since \(3333+3333=6666\) base 7, it cannot also be \(1000\) base seven as well that is for sure, so scratch (iii)

Answer 8

Lol, I think they do. Oh, the best part is I still pay for them but it doesn't count as any credits.

Answer 9

i think both (i) and (ii) are right

Answer 10

they are both 2400 base ten

Answer 11

as a matter of fact i am sure of it

Answer 12

oops missed the fact there's still a \(7^0\) there!

Answer 13

go with C (i) and (ii) are true

Answer 14

Thanks everyone

Answer 15

yw

Answer 16

6666 base 7 = 6*7^3 + 6*7^2 + 6*7^1 + 6*7^0 base 10

6666 base 7 = 2400 base 10

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now convert to base 12

2400/12 = 200 remainder 0

200/12 = 16 remainder 8

16/12 = 1 remainder 4

1/12 = 0 remainder 1


read the remainders from bottom to top to get 1480

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so this means

6666 base 7 = 2400 base 10 = 1480 base 12