Question

The sum of squares formula is given by 1^2+2^2+3^2+…+n^2=n(n+1)(2n+1)/6. The sum of odd squares can be expressed as 1^2+3^2+5^2+…+(2n−1)^2=An^3+Bn^2+Cn+D. The value of A can be expressed as a/b, where a and b are positive coprime integers. What is the value of a+b?

Answer 1

1^2+3^2+5^2+…+(2n−1)^2 = 4/3 n^3 - 1/3 n
therefore, A = 4/3 = a/b
so, a+b = .... ?

Answer 2

is it 5?????

Answer 3

a/b = 4/3
obviously a=4 and b=3 (with a and b are positive coprime integers)
so, a+b = 4 + 3 = ... ?

Answer 4

7

Answer 5

yes