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Chemistry 17 Online
OpenStudy (anonymous):

hi there! can anyone help me with this? :) Arrange the following elements in order of increasing atomic size, and explain how you know the order: Ca, Rb, S, Si, Ge, F. Do not simply state the trends but rather explain why the trend exists

OpenStudy (chmvijay):

can you tell me in which row these elements come in periodic table example Ca-4 th row like that can you write for all

OpenStudy (anonymous):

F-2nd row S-3rd row Si-3rd row Ca-4th row Ge-4th row Rb-5th row

OpenStudy (chmvijay):

ok good:)

OpenStudy (chmvijay):

remember in the same row as we move from left to right the atomic radius decreases and as we go down the same group the atomic radius increases

OpenStudy (chmvijay):

now Flourine is present in the 2nd row and it is at the extreme right side hence otut of all its is the smallest right

OpenStudy (chmvijay):

now let us move to 3rd row where these elements are bigger than the 2nd row elements. in 3 rd row we have two elements that is S and Si as i told in the same row as u go from left to right atomic size decreses and in 3 rd row as u go from left to right you get first Si and later u get sulfur therefore Si is bigger than the S now u got this order F<S<Si are u getting it ???

OpenStudy (anonymous):

I think so

OpenStudy (chmvijay):

good:) now in 4 hr row Ca comes first then the Ge hence Ca is bigger than the Ge now u have order F<S<Si<Ge<Ca

OpenStudy (chmvijay):

and last one u write as Rb F<S<Si<Ge<Ca <Rb

OpenStudy (chmvijay):

theoretical atomic size are as given below F=0.42 S=0.88 Si=1.11 Ge=1.25 Ca=1.94 Rb=2.65 so our Predication and the method is right did u get it or nooo:)

OpenStudy (anonymous):

yes, thank you.....

OpenStudy (chmvijay):

you are welcome :)

OpenStudy (anikhalder):

@chmvijay Thanks

OpenStudy (chmvijay):

hey ur welcome:)

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