Question

((sinx)^4/(tanx)^2 ) Simplify.

Answer 1

=\[\frac{sinx^{4}}{(\frac{sinx^2}{cosx^2})}=\frac{sinx^{4}cosx^{2}}{sinx^{2}}\]

Answer 2

= sin^2cos^2

Answer 3

when we simplify the @zzr0ck3r answer:
we get
\[\huge \frac{sinx^4cosx^2}{sinx^2}\]
\[\huge = sinx^2cosx^2\]

Answer 4

ok... @TabletofDaFuta

Answer 5

o thats the most simplified...? i got it right then lololol but thx

Answer 6

welcome:)