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Verify the following identity used in calculas: (cos(x+h) - cosx)/h = (cosxcos(h-1))/h = (sinxsinh)/h
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definition of derivative \[\lim _{h->0} \frac{\cos(x+h) -\cos x}{h} = \lim _{h->0} \frac{\cos x \cos h - \sin x \sin h -\cos x}{h} =? -\sin x\] not sure how to prove it but i know the answer
\[= -\cos x \lim_{h->0}\frac{1-\cos h}{h} - \sin x \lim _{h->0} \frac{\sin h}{h}\] \[= -\cos x *0 - \sin x * 1\] \[= - \sin x\] http://en.wikipedia.org/wiki/Trig_identities#Calculus
dont get it right now but i might tomorrow. thanks
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