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OpenStudy (anonymous):
when a polynomial f(x)divided by (x-1)it gives remainder 4 &when divided by (x-2) remainder=5 what will be remainder if f(x)is dividedby (x-1)(x-2)
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OpenStudy (anonymous):
love remainder/factor theorem
OpenStudy (anonymous):
P(x)=Q(x)D(x)+R
OpenStudy (amistre64):
\[\frac{x-1+4}{x-1}\]
\[\frac{x-2+5}{x-2}\]
since f(x) = x+3 is "a" solution .... i wonder if we can be this specific
OpenStudy (anonymous):
i think we look more at the remainder theorem here.
OpenStudy (anonymous):
For this speicfic question P(x)=Q(x)(x-1)(x-2)+(Ax+B)
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OpenStudy (anonymous):
The remainder is a linear factor as it is 1 degree lower than a quadratic
OpenStudy (anonymous):
Is this guy online?
OpenStudy (amistre64):
prolly not .... but the question was nice
OpenStudy (anonymous):
Anyway we know P(1)=4 from first lot of info
and P(2)=5
OpenStudy (anonymous):
now its just simultaneous equations
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OpenStudy (anonymous):
So we get
A+B=4
2A+B=5
OpenStudy (anonymous):
A=1 B=3
OpenStudy (anonymous):
tHEREFORE remainder is x+3
OpenStudy (amistre64):
so i was right :)
OpenStudy (anonymous):
which is what u got i guess haha
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OpenStudy (anonymous):
i gotta hand it to you
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