The angle a rotating shaft turns through in t seconds which is given by..
\[\theta=\omega t+\frac{ 1 }{ 2 }\alpha t ^{2}\] Determine the time taken to complete 4 radians if \[\omega \] is 3.0 rad/s and \[\alpha \] is 0.60 rad/s^2
so isnt it just 4 = 3t + 1/2 *.6*t^2...?
so solve for t using quadratic solution after putting in the form of 0 = ax^2 + bx + c
answers are t = -11.19 and t = 1.19 so it will turn 4 radians 11 seconds before you turn it on ... OR it will turn 4 radians 1.2 seconds after you turn it on take your pick @WilliamF
How did you rearrange it into a quadratic?
sorry dude, was looking at another post, back now
no worries
you already had the form there theta = bx + (a) x^2 so theta is -c rearrange so it equals 0 0 = ax ^2 + bx + c you get your c as -4 your b as 3 (angular velocity) and your a as .5*.6 = 0.3 (half angular acceleration) ... done ;)
and in this example x = time = t
ok I get it now, thanks for the help Jack
always welcome dude
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