I NEED HELP???!!!!!~
State whether the given measurements determine zero, one, or two triangles. B = 84°, b = 28, c = 25
|dw:1370972702800:dw| A+C = 96 both must be acute angles therefore only 1 triangle can be formed
thank you, you been so helpful do you mind if i ask one more question
Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. B = 46°, a = 12, b = 11 A = 38.3°, C = 95.7°, c = 8; A = 141.7°, C = 84.3°, c = 8 A = 51.7°, C = 82.3°, c = 8; A = 128.3°, C = 5.7°, c = 8 A = 38.3°, C = 95.7°, c = 15.2; A = 141.7°, C = 84.3°, c = 15.2 A = 51.7°, C = 82.3°, c = 15.2; A = 128.3°, C = 5.7°, c = 1.5
wait sorry , technically you could have obtuse angle like 92 and other angle be 4 but since 25 < 28 .... angle C is less than 84 and using law of cosines ... a = 15.5, so angle A must be less than angle C therefore both are acute
so there are two triangles
no same argument.....just giving better explanation you only get 2 triangles if an unknown angle can actually be either an acute or obtuse angle this comes from Law of sines, where there are always 2 solutions to sin A = b
oh gotcha
law of sines: \[\frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c}\] the reciprocal is also true \[\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\]
i am not going to go through all those problems...use the formula and try to work them out on your own use wolframalph.com to check answers :)
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