Question

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Answer 1

The inverse variation is written as

\[y = \frac{ k }{ x }\]

So since you have 'y' and 'x' you can plug those into that equation to solve for 'k'

\[8 = \frac{ k }{ 2 }\]

so k = 8 times 2

k = 16

So for your question

\[y = \frac{ 16 }{ x }\]

Answer 2

I hope that makes sense! :)

Answer 3

Thank you so much!

Answer 4

Anytime :)