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Mathematics 9 Online
OpenStudy (anonymous):

IS my answer right ?????????????

OpenStudy (anonymous):

Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. B = 46°, a = 12, b = 11

OpenStudy (anonymous):

A = 51.7°, C = 82.3°, c = 15.2; A = 128.3°, C = 5.7°, c = 1.5

OpenStudy (anonymous):

@Anu2401 @e.mccormick @cwrw238 @Falco276 @IrishBoy @ivandelgado @johnweldon1993 @kropot72 @ogkat @Preetha @RaphaelFilgueiras @thomaster

OpenStudy (anonymous):

can any help

OpenStudy (e.mccormick):

First OK. Still checking second.

OpenStudy (anonymous):

ok thnx

OpenStudy (e.mccormick):

Helps when I put the riht numbers in the calculator.... looks good.

OpenStudy (anonymous):

wow thnx i have one more that im confuse about @e.mccormick if you dont mind

OpenStudy (anonymous):

Find the fourth roots of 256(cos 280° + i sin 280°).

OpenStudy (e.mccormick):

DeMoivre’s Theorem Let \(z = r[\cos(θ) + i\sin(θ)]\) and n be a positive integer. Then \(z^n=r^n[\cos(n\theta)+i\sin(n\theta)]\)

OpenStudy (anonymous):

Let y=256(cos 280+i sin 280) Now this[(cos 280+i sin 280)] can be written in exponential form as exp^(i*280) We need to find y^(1/4) Hence =>[256*exp^(280i)]^(1/4) =>4*exp^(70i) =>4(cos70+isin70) Ans

OpenStudy (anonymous):

i dont understand the formula the second one what is r 256

OpenStudy (e.mccormick):

So you do your \(256^4\) and put that out front, then multiply the angles by 4, then simplify a bit (can reduce the angles to \(0^\circ\le 360^\circ\)

OpenStudy (e.mccormick):

Oops. Yah, root.... I want the wrong direction.

OpenStudy (anonymous):

ok @Anu2401 what is after that

OpenStudy (e.mccormick):

Anu2401's /(r^{\frac{1}{4}} is right. Going to the root rather than the power.

OpenStudy (e.mccormick):

\(r^{\frac{1}{4}}\)

OpenStudy (anonymous):

so is he right at that step

OpenStudy (anonymous):

im trying to take notes

OpenStudy (anonymous):

@Easycheddar Yes the solution is correct . Just go through de-moiver's theorem once .... Google It :)

OpenStudy (e.mccormick):

Absolutly. Because they said 4th root. It is the same thing as this:\[\sqrt[4]{x}=x^{\frac{1}{4}}\]

OpenStudy (anonymous):

http://en.wikipedia.org/wiki/De_Moivre's_formula See application part

OpenStudy (anonymous):

ok so that the solution now i just need to do the therom

OpenStudy (e.mccormick):

I went tot he 4th power in my explanation... the question aid 4th root. My mistake there.

OpenStudy (anonymous):

so what the answer cause i am getting something crazy @e.mccormick and @Anu2401

OpenStudy (anonymous):

U can put the value of cos 70 & Sin 70 in last step . Use a calculator to find the values of those

OpenStudy (e.mccormick):

Did you start with: \[256^{\frac{1}{4}}\left(\cos \frac{280^\circ}{4} + i \sin \frac{280^\circ}{4}\right)\]And follow how Anu2401 did it? Also, is your calculator in Degrees or Radians mode?

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