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Mathematics 7 Online
OpenStudy (anonymous):

x^2+y^2=1 Decide whether y is a function of x

OpenStudy (anonymous):

someone wanna help a girl out

OpenStudy (e.mccormick):

Have you graphed it? If you look at the graph, then you can try a vertical line test.

OpenStudy (anonymous):

no but one sec i'll try it

OpenStudy (anonymous):

do i graph it like a circle or line?@e.mccormick

OpenStudy (e.mccormick):

A circle! And because it is a circle, what would that mean for the vertical line test?

OpenStudy (anonymous):

it fails it

OpenStudy (anonymous):

so it's not a function of x

OpenStudy (anonymous):

right @e.mccormick

OpenStudy (e.mccormick):

https://www.desmos.com/calculator/rgzrjjypri Exactly!

OpenStudy (anonymous):

what about 2x+y=7 @e.mccormick that is a function correct?

OpenStudy (e.mccormick):

If you solve that for y, what do you get? Something that would graph as a line, or another thing that curves and fails the test?

OpenStudy (anonymous):

line so yes it is @e.mccormick ty!!!!!!!!!!!!!!!!!!!!!

OpenStudy (e.mccormick):

Any line or basic curve that passes the vertical line test is a function. Any curve that folds over to the point where it back tracks at all will fail. Any set of x and y pairs, like \((x_1,y_1),\, (x_2,y_2),\, (x_3,y_3),\) etc. where the same x value has different y values fails. As you can see, it is just a bunch of really simple tests. Pass or fail. Sorry about the reply delays, but the site keeps telling me it is loading.... =/

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