Question

find (fg)(x) ???

Answer 1

Just tmultiply the two functions

Answer 2

when it's said to get a "function of a function"
it really means, replace the variable on the "host" function by the "guest" function

so the "x" in the denominator of f(x), will become \(x^2-3 then you add the 6, and that's your new denominator for (fog)(x)

Answer 3

woops darn

Answer 4

gf

Answer 5

when it's said to get a "function of a function"
it really means, replace the variable on the "host" function by the "guest" function

so the "x" in the denominator of f(x), will become \(\color{green}{x^2-3}\) then you add the 6, and that's your new denominator for (fog)(x)

Answer 6

@pauli is it ..... f times g (x) or ... f of g (x)?

Answer 7

maybe is just a simple multiplication :/

Answer 8

it is

Answer 9

alright, that looks like a simple multiplication, as FutureMathProfessor suggested, just multiply both