Question

find the limit as x approaches infinity of x^2+x/3-x thanks

Answer 1

An explanation of how to solve limits approaching infinity would be helpful. Thanks :)

Answer 2

l'hopital's rule

Answer 3

so the answer would just be 2x

Answer 4

ahemm, something tells me joshy12 is not doing l'hopital yet if at all

Answer 5

Do you know l'hopital's rule joselin?

Answer 6

jdoe, actaully i do

Answer 7

there is no horizontal asymptote but there is a limit , its just that it goes to neg infinity

Answer 8

@joselin12 ohh, okie dokie

Answer 9

Activate l'hopital's rule and plug in infinity and tell me what you get

Answer 10

\[\frac{( x^2-x)' }{(3-x)' }=\frac{ 2x-1 }{ -1 }=-2\infty-1= -\infty\]

Answer 11

When I do l'hopital's rule i get 2x..

Answer 12

You can't divide by parts! Look at how I did my operations

Answer 13

Isn't it suppose to be 2x+1 ?

Answer 14

I guess so, but it's irrelevant

Answer 15

-2x+1