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Find the derivative of :
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\[\huge (\frac{ 1 }{ 3 }) ^{4x} -2e^{sinx} \]
the derivative of \(b^x\) is \(b^x\ln(b)\) that should help for the first one
that, plus chain rule (for both)
\[\large y'=(4\ln \frac{ 1 }{ 3 }) (\frac{ 1 }{ 3 })^{4x}-2e^{sinx}(cosx)\] @satellite73
That's the answer at the back of my book but where did the 4 before ln comefrom ?
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