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Mathematics 16 Online
OpenStudy (anonymous):

What is the x-intercept of this piecewise function?

OpenStudy (anonymous):

OpenStudy (anonymous):

|dw:1371007718302:dw| x-intercept, when y = 0

OpenStudy (anonymous):

Heres some of the answers. I can only see how it crosses at (0,0)

OpenStudy (whpalmer4):

Okay, the correct answer is on that list...why don't you tell us what you think about each choice?

OpenStudy (whpalmer4):

Here's a graph of the function from x=-2 to x=5

OpenStudy (anonymous):

Well, I can see how it crosses the x axis at the origin. But I can't help but this there is more than one right answer

OpenStudy (anonymous):

*can't help but think

OpenStudy (whpalmer4):

Well, go through the list and tell us whether you think each one is possible or not. Explaining something to someone else is a great way to test and build your understanding.

OpenStudy (anonymous):

you'll want to go through and see if the piecewise f(x) can = 0 within any of the 3 domains

OpenStudy (anonymous):

I don't think the first one is possible, because as the graph shows, it doesn't cross at (2,0)

OpenStudy (whpalmer4):

That's correct. Go on...

OpenStudy (anonymous):

the second one was wrong because it does cross the x axis

OpenStudy (whpalmer4):

Correct again...

OpenStudy (anonymous):

Also, from the graph I see that it does cross at (16,0)

OpenStudy (whpalmer4):

Are you sure about that?

OpenStudy (anonymous):

I guess it doesn't, it just kinda...starts a different way once it gets there

OpenStudy (anonymous):

it does cross at the origin and it doesn't cross at (0.5,0)

OpenStudy (whpalmer4):

No, the last section starts at x = 4, not x = 16... it has y = 16 at that point, not x...

OpenStudy (anonymous):

Oh,Okay I get that

OpenStudy (whpalmer4):

Here's a bigger picture graph

OpenStudy (whpalmer4):

As you can see, at x = 16, it's nowhere near the x-axis... Only 1 correct answer, agreed?

OpenStudy (anonymous):

Right then, so it does cross at the origin. Which is my answer.

OpenStudy (whpalmer4):

Yep, that's the only correct choice.

OpenStudy (anonymous):

Thanks for going through it with me

OpenStudy (whpalmer4):

You're welcome, of course!

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