Question

How is this done? Sec theta -costheta divided by tan theta =sintheta

Answer 1

\[\frac{\sec x -\cos x}{\tan x}\]
\[= \frac{\sec x}{\tan x} - \frac{\cos x}{\tan x}\]
\[= \frac{1}{\cos x}*\frac{\cos x}{\sin x} - \cos x *\frac{\cos x}{\sin x}\]
\[= \frac{1-\cos^{2} x}{\sin x}\]
\[= \frac{ \sin^{2} x}{\sin x}\]
\[=\sin x\]

Answer 2

Thanks alot

Answer 3

yw