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If x=f(t) and y=g(t) then d^2y/dx^2?
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\[\LARGE \frac{dy}{dx}=\frac{g'(t)}{f'(t)}\]
\[\LARGE \frac{d^2y}{dx^2}=\frac{f'g''-g'f''}{(f')^2}\] im getting this..
@terenzreignz @ParthKohli
Seems right
But is wrong.
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I'd have to look further. Probably the first step is incorrect.
:O
\[\LARGE \frac{d^2y}{dx^2}=\frac{f'g''-g'f''}{(f')^2}\] you are taking the derivative w.r.t. x not t. that is why this is wrong. your first derivative is correct
how will we differentiate wrt x?
okay,thanks I got it! just cube in denominator :D
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