The test to detect the presence of the hepatitis B virus is 97% accurate for a person who has the disease and 99% accurate for a person who does not have the disease. If 0.55% of the people in a given population are infected, what is the probability that a randomly chosen person gets an incorrect result?

0.98455

0.000165

0.009945

0.001011

Question

The test to detect the presence of the hepatitis B virus is 97% accurate for a person who has the disease and 99% accurate for a person who does not have the disease. If 0.55% of the people in a given population are infected, what is the probability that a randomly chosen person gets an incorrect result?

0.98455

0.000165

0.009945

0.001011

anonymous · Answer

I really need help :/

anonymous · Answer

0.0055*0.03+0.9945*0.01= should give you the ans

anonymous · Answer

add the chances that when they pick infected or uninffected they'll make an error, i think

anonymous · Answer

Thank you ! now can you tell me how you go that? besides turning the percentages to decimals. where the the .03 to the .01 come from?

anonymous · Answer

hopefully one of the options will be the result (:

anonymous · Answer

.03 and .01 are the probability of an error being made in infected and unnifected respectively

anonymous · Answer

I have another one with basically the same thing could you walk me through it?

anonymous · Answer

yeah, i can try

anonymous · Answer

0.001011