Show that x/a+y/b=1 touches the curve y=b (e)^(x/a) at the point where the curve crosses y-axis
I am guessing that they will TOUCH each other if they both have equal tangents at any point (a,b)
Therefore,tangent of 1st one=>b/a tangent of 2nd one=>b (e)^(x/a) itself?i am confused do we have to take log or not.. am i going correct?
Hmm, if they "touch", that should mean that they `intersect` at some point, right? \[\large \frac{x}{a}+\frac{y}{b}=1 \qquad\qquad \rightarrow\qquad\qquad y=b-b\frac{x}{a}\] Setting them equal to one another,\[\large b-b\frac{x}{a}=b e^{x/a}\] And then ummm simplifying some stuff down..\[\large 1-\frac{x}{a}=e^{x/a}\] This only holds true for one particular x value, do you know which one? :D The tangent line thing is interestinggggg, I'm not sure where it's leading us though. Seems to make more sense though, since this is a calculus problem lol.
touching and intersecting are different things.............
Why would they be different..?
if they are TOUCHING.. |dw:1371142229661:dw| then the tangent at any point say alpha,beta is same |dw:1371142302026:dw| here tangent at any point alpha,beta is not same
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