Question

How would you solve this expression?

Answer 1

\[\Huge \sqrt{7+\sqrt{48}}=\sqrt{m}+\sqrt{n}\]
solve for m^2+n^2

Answer 2

\[\sqrt{7+\sqrt{48}}=\sqrt{7+2\sqrt{12}}\]

m+n=7 and m*n=12

m=3 n=4 or m=4 n=3
3^2+4^2=9+16=25

Answer 3

how did you get all that?
m+n=7 and m*n=12 m=3 n=4 or m=4 n=3 3^2+4^2=9+16=25

Answer 4

\[(\sqrt{m}+\sqrt{n})^{2}=m+n+2\sqrt{mn}\]
\[m+n+2\sqrt{mn}=7+2\sqrt{12 }\]
do you understand?

Answer 5

oh hmm okay thanks

Answer 6

you're welcome :)

Answer 7

how can we compare btw,3 terms on one side 2 on other? :O

Answer 8

m+n is just one term like 3+4. it's 7. did you get?