Question

what is the perimeter of a right triangle in which th longer leg is 4 units longer than the hypotenuse ?

Answer 1

the thing has to add up to one 80 and the hypotneuse has to be bigger than both sides do have multiple choice so i can explain better?

Answer 2

u do need help still right @veunta&NuNu

Answer 3

a:) 12units
b:)16units
C:)20 units
D:)48 units

Answer 4

do you know which are the another side besides 4 is? and i meant 180 in my first reply

Answer 5

no

Answer 6

do u know the formular \[c ^{2}=a ^{2}+b ^{2}\]

Answer 7

yes

Answer 8

ok c^2=4+b^2, it has to eaqul 360 from being squared and then add regular a+b+c to get the perimiter understand?

Answer 9

yeah i kinda understand ,,,is it anyway other way you can helpp me to find the answer

Answer 10

text the theory \[c ^{2}=4^{2}+b ^{2}\]

Answer 11

4*4=16
so c^2=16+b^2

Answer 12

that is the star of your perimitor but lets show you how to get 360 first

Answer 13

4+_=360

Answer 14

that would be what?

Answer 15

56

Answer 16

now split 56

Answer 17

28

Answer 18

28 and what?

Answer 19

then what ?

Answer 20

ok so 4^2+28^2=28^2 is what

Answer 21

here u want me to show u a diff way?

Answer 22

5

Answer 23

Let the longer leg be X ok?
Then the snorter leg must be X-4
Now the Pythagorean Theorem tells us that in right-angled triangles,
(short leg)^2 + (longer leg)^2 =hypotenuse^2
(X-4)^2 +( X )^2 = 6^2
X^2 -8X + 16 + X^2 =36
2X^2-8X-20 =0
X^2 -4X -10=0
understand so far?

Answer 24

should i keep going?

Answer 25

yes

Answer 26

At this point I can't factor by eye-balling it, so I'll have to use the quadratic formula
That formula says X= {-b+ or - sq rt(b^2-4ac)}/2a'
where a =X^2 coefficient, in this case +1
b=X coefficient, in this case -4
c == constant term, in this case -10

X= {-(-4)+ or - sqrt(-4^2 -4(1)(-10)}/2
X ={4 + or - sqrt(16+40)}/2
X ={4 + or - sqrt(56)}/2
X={4 + or -sqrt4(sqrt14)}/2
X={4 + or - 2rt14}/2
X=2{2+ or -rt14}/2
X= 2+ rt14 or 2 -rt14

rt14= 3.74
So, X = 5.74 or -1.74 Clearly -1.74 is out. Therefore the side X is 5.74and since this is the longer leg, the shorter leg must be 5.74-4=1.74
Let's check our work.
(5.74)^2 + (1.74)^2 =36
32.95 +3.03=36
35.98 = 36

Answer 27

i rounded that to 48 understand?

Answer 28

yes i understand can you hel[p me with the next qestion

Answer 29

sure

Answer 30

if the length of the hypotenuse ofan isosceles right triangle is 12cm,what is the length of each of the other two sides ?

Answer 31

Use Pythagoras' Theorem
a² + b² = 12²
The triangle is isosceles so a=b
2a² = 12²
a² = 72
a = 6√2 ≈ 8.49cm
The lengths of each of the other two sides are about 8.49cm
You could also use the fact that the angles of the triangle would be 90°, 45° and 45° and use the sin and cos values of 45° (sin45° = cos45° = 1/√2) to arrive at the same result.
understand???

Answer 32

answer would be ?

Answer 33

about 8.49

Answer 34

answer choices are 5^2 , 6 cm ,6^2 cm ,or 7 cm

Answer 35

then 7, rounding

Answer 36

if the length of the hypotenuse of an isosceles right triangle is 14cm,what is the lenght of the other two sides

Answer 37

come on bud its the same thing lol you try it and i'll help, show me what we do first