Do any of you go to CA and take Algrebra? I NEED HELP!
@onedirection822 can you fan me? it says i can't message you back unless you do.
What's the question?
@Peasant1 actually questions i really suck at algebra .__.
Post the questions here so we can help you :]
Yeah. Algebra comes pretty easy to me so if you post the question or a screen shot we could help. :)
ok hold on (:
Alright!
OK so, the way to solve this is quite simple.
i dont get where to start at
For the first part of the question we'll use -4x+3y=-12
Quick question, do you have a graphing calculator?
no i do not D:
That stinks... Well... I do. maybe I could help explain it in a way you could understand... first lets get the first equation in a way we can use it.
so, with -4x + 3y = -12 we need to get y on one side by itself.
so dont you have to multiply -4x by 0?
no
we have to add 4 x to both sides. We then get 3y=4x-12
Make sense?
yeah i get it (:
ok so now divide 3 by both sides so that you get y by itself. It should look like this: y = 4x/3 - 4 Still with me?
ok got it .
Ok now, leave that equation like it is. It's ready to be used but now we have to get the other one ready. -2x + 3y = -18
We need to get y by itself again. What do we do first?
we move the -2x, which i got y=2x/3-6?
Great job! Now, we have to graph those equations. That's going to be hard for you meaning you don't have a graphing calculator.
Peasant1, can I suggest something?
sure.
You have: y = 4x/3 - 4 y = 2x/3 - 6 If you do, 4x/3 - 4 = 2x/3 - 6 You will find the point where the two functions intersect. After that, you only have to search that point on the options.
haha I completely overlooked that method. lol I always do it this way but that way works just as well... :P
:) Solving the equation, you will find x = -3. y = 4x/3 - 4 y = 4*-3/3 - 4 = -4 - 4 = -8 The intersection point is (-3, -8). Letter B.
omg thank you i get it now (:
haha yup the way I got it was by graphing the two equations on my calc.
haha Awesome @lunitaboo ! See it's not too hard. ;)
ha thanks ! you guys are nice btw (:
you're welcome :]
Your welcome!
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